Answer: I Think It Is Greater Than Or Equal To -9
Step-by-step explanation: The given function is:
f(x)x^2+2x-8
We complete the square to write this function in the form:
f(x)=a(x-h)^2+k
We add and subtract the square of half the coefficient of x.
f(x)=x^2+2x+1^2-1^2-8
f(x)=(x=1)^2-9
The vertex of this function is (h,k) which is (-1,-9)
The equation of axis of symmetry is x=h
But h=-1, hence the axis of symmetry isx=-1
To find the x-intercepts, we put f(x)=0
(x+1)^2-9=0
(x+1)^2=9
x+1=the square root of 9
x=-4, 2
The x-intercepts are:(
-4,0) and (2,0)
The given function is a polynomial function, the domain is all real numbers
The function has a minimum value of y=-9.
Therefore the range is y|y is greater that or less than -9