Answer:
312.5 mL
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HNO₃ + NaOH —> NaNO₃ + H₂O
From the balanced equation above,
The mole ratio of acid, HNO₃ (nₐ) = 1
The mole ratio of base, NaOH (n₆) = 1
Finally, we shall determine the volume of the base, NaOH needed for the reaction. This can be obtained as follow:
Molarity of base, NaOH (M₆) = 0.08 M
Volume of acid, HNO₃ (Vₐ) = 125 mL
Molarity of acid, HNO₃ (Mₐ) = 2 M
Volume of base, NaOH (V₆) =?
MₐVₐ / M₆V₆ = nₐ/n₆
2 × 125 / 0.80 × V₆ = 1/1
250 / 0.80 × V₆ = 1
Cross multiply
0.80 × V₆ = 250
Divide both side by 0.8
V₆ = 250 / 0.8
V₆ = 312.5 mL
Thus, the volume of the base, NaOH needed for the reaction is 312.5 mL