Question

To make hot chocolate for you and your friends, you must melt 3.0 kg of snow (0.0°C) and heat it to 70.0°C to make the hot chocolate. Calculate the total amount of heat needed.

Heat of fusion of ice = 3.34 × 10^5 J/kg, Specific Heat of Water = 4180 J/(kg.K)

Answer 1

Answer:
`18.798* 10^5\ J`

Step-by-step explanation:

Given

Mass of snow is
`m=3\ kg`

First snow is converted to water at
`0^(\circ)C` and then it is taken to
`70^(\circ)C`

Heat required to convert the ice into water at
`0^(\circ)C`

`Q_1=3* 3.34* 10^5\\Q_1=10.02* 10^5\ J`

Heat required to raise temperature from
`0^(\circ)C` to
`70^(\circ)C`

`Q_2=3* 4180* (70-0)\\Q_2=8.778* 10^5\ J`

Total heat required

`\Rightarrow Q=Q_1+Q_2\\\Rightarrow Q=10.02* 10^5+8.778* 10^5\\\Rightarrow Q=18.798* 10^5\ J`