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A solid cube of material is 1.50 cm on the edge. It submerged totally in oil of ρ = 820 kg/m3 .Find the buoyancy force of the material.​

User Khelben
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2 Answers

6 votes

Answer:

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Step-by-step explanation:

User Arkadiusz Konior
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3.7k points
4 votes

Answer:

0.027 N

Step-by-step explanation:

From the question,

According to Archimedes principle,

The buoyancy force on the material = weight of oil displaced by the solid cube = Upthrust on the solid cube.

Applying,

U =ρ×V×g................ Equation 1

Where U = Upthrust on the solid cube, ρ = density of oil, V = Volume of the solid cube, g = acceleration due to gravity

But,

V = l³................ Equation 2

Substitute equation 2 into equation 1

U = gρl³.............. Equation 3

Given: ρ = 820 kg/m³, l = 1.50 cm = 0.015 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

U = 820×0.015³×9.8

U = 0.027 N

User Samach
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