Question

If an arrow is shot upward on the moon with a velocity of 50 m/s, its height (in meters) after t seconds is given by H = 50t − 0.83t^2.

Answer 1

The velocity is: 48.34m/s

Explanation:

Given

`u = 50m/s` --- initial velocity

`h = 50t - 0.83t^2`

Required

The velocity after 1 second

We have:

`h = 50t - 0.83t^2` and
`t = 1`

Differentiate

`h' = 50 - 1.66t`

We have that:

`v = h'`

So, the equation becomes

`v = 50 - 1.66t`

Substitute 1 for t

`v = 50 - 1.66*1`

`v = 50 - 1.66`

`v = 48.34`