How many liters of phosphine are produced when 34 L of hydrogen reacts with an excess of phosphorus under STP?

asked Mar 2, 2022 64.7k views

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Answer:

22.67 L of PH₃

Step-by-step explanation:

The balanced equation is:

$P_4 (s) + 6H_2(g) \to 4PH_3(g)$

From the equation:

$34 L * (1 \ mol \ of H_2 )/(22.4 \ L \ H_2) * (4 \ mol \ of \ PH_3)/(6 \ mol \ H_2) * (22.4 \ L \ PH_3)/(1 \ mol \ PH_3)$

= 22.67 L of PH₃

Herz Rod answered Mar 5, 2022

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