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A sample of gas at 500 mm Hg inside a steel tank is cooled from 773 K to 273 K. What is the final pressure of the gas in the steel tank?

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Answer:

177 mmHg

Step-by-step explanation:

Given that:

The sample of a gas is with Pressure (1)
P_1 = 500 mmHg

The initial temperature
T_1 = 773 K

The final temperature
T_2 = 273 K

Using ideal gas equation:


(P_1)/(T_1) = (P_2)/(T_2) \\ \\ (500)/(773) = (P_2)/(273) \\ \\ (136500) = 773 * P_2 \\ \\ P_2 = (136500)/(773) \\ \\ P_2 = 176.58 \ mmHg \\ \\ \simeq 177 mmHg

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