Question

You react hydrogen gas with chlorine gas according to the following reaction:

H2(g) * Cl2(g) -> 2HCl(g)
What mass of HCl(g) can be produced from 2.5 * 10^3 g of hydrogen gas with an excess of chlorine gas?

Answer 1

91150 g

Step-by-step explanation:

• H₂(g) + Cl₂(g) → 2HCl(g)

First we convert 2.5x10³ g of hydrogen gas into moles, using its molar mass:

• 2.5x10³ g ÷ 2 g/mol = 1250 mol

Then we convert 1250 moles of H₂ into HCl moles, using the stoichiometric coefficients of the reaction:

• 1250 mol H₂ *
  `(2molHCl)/(1molH_2)` = 2500 mol HCl

Finally we convert 2500 moles of HCl into grams, using its molar mass:

• 2500 mol HCl * 36.46 g/mol = 91150 g