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156 grams of calcium fluoride, CaF2, is dissolved in 2000 mL of solution. Determine the molarity (M).

1 Answer

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Answer:

1 M

Step-by-step explanation:

We'll begin by calculating the number of mole of in 156 g of CaF₂. This can be obtained as follow:

Mass of CaF₂ = 156 g

Molar mass of CaF₂ = 40 + (19×2)

= 40 + 38

= 78 g/mol

Mole of CaF₂ =?

Mole = mass /molar mass

Mole of CaF₂ = 156 / 78

Mole of CaF₂ = 2 moles

Next, we shall convert 2000 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

2000 mL = 2000 mL × 1 L / 1000 mL

2000 mL = 2 L

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of CaF₂ = 2 moles

Volume = 2 L

Molarity =?

Molarity = mole / Volume

Molarity = 2 / 2

Molarity = 1 M

Thus, the molarity of the solution is 1 M

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