Question

Help me out??

H2SO4(aq) + 2 KOH(aq) --> 2 H2O(l) + K2SO4 (aq)

If you have 2 moles of H2SO4, how many moles of KOH do you need?

Answer 1

4 mol KOH

Step-by-step explanation:

Step 1: Write the balanced neutralization reaction.

H₂SO₄(aq) + 2 KOH(aq) ⇒ 2 H₂O(l) + K₂SO₄(aq)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of H₂SO₄to KOH is 1:2.

Step 3: Calculate the number of moles of KOH needed to react with 2 moles of H₂SO₄

We will use the previously established molar ratio.

2 mol H₂SO₄ × 2 mol KOH/1 mol H₂SO₄ = 4 mol KOH