Question

PLEASE HELP!!!!1!1!1! suppose one particular pyramid in egypt has a square base of side length 280 meters and a perpendicular height of 144 meters what is the surgace area of the pyramid?

Answer 1

Pyramid Surface Area = .5 * Perim of Base * Slant Height

Slant Height^2 = 144^2 + 140^2

Slant Height^2 = 20,736 + 19,600

Slant Height^2 = 40,336

Slant Height = 200.8382433701

Surface Area = .5 * perim of base * slant height

Surface Area = .5 * 1,200 * 200.8382433701

Surface Area = 120,503 square meters

Source = www.1728.org/volpyrmd.com

Explanation: