Answer:
Given system of inequalities:
![\large\begin{cases}y < (2)/(3)x\\y\geq-x+2\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/high-school/amodgfbx8319yhw7d44jjfsiexb5pd5ewl.png)
When graphing inequalities:
- < or > = dashed line
- ≤ or ≥ = solid line
- < or ≤ = shade below the line
- > or ≥ = shade above the line
![y < (2)/(3)x](https://img.qammunity.org/2023/formulas/mathematics/high-school/ophmm7plbsox1lbl1auds1bpx1pesls27s.png)
The slope of the first inequality is 2/3, therefore at x = 1, y = 2/3.
So the correct line for the first inequality is the dotted line with the shallower slope.
As the relation is < for this inequality, the shading should be below the dotted line.
![y\geq-x+2](https://img.qammunity.org/2023/formulas/mathematics/high-school/9ax53btp8rzr57duc2lnfgz419x6m38jnx.png)
From inspection of the given graphs, the line of the second inequality (solid line) is the same in all graphs.
As the relation is ≥ for this inequality, the shading should be above the solid line.
Therefore, the only graph that satisfies these conclusions is graph D (attached).