Given
P1 = 1 Atm ( at stp)
V1 = 3.00 L
V2 = 3.20 L
P2 = ?
We know that,
at constant temperature
P1V1 = P2V2
1 × 3 = 3.2 × P2
P2 = 3/3.2
P2 = 0.9375 Atm
pressure at 3.2 L is 0.9375 Atm.
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