Answer:
y( y^2+1+2y+2)
Explanation:
taking common of all
Given equation, 2x
3
+3x
2
+3x+1=0
⟹2x
+2x
+x
+2x+x+1=0⟹(2x+1)(x
+x+1)=0
Solving the 2 equations, we have x=
−1
,
−1±
i
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