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PLEASE help — I’m failing!

Determine each of the following for a 4.23 x 10-3 M solution of HCl:
a. H3o+
b. OH-
c. pH
d. pOH

1 Answer

2 votes

Answer:

a.


[H _(3)O {}^( + ) ] = 4.23 * {10}^( - 3) M

b.


[OH {}^( - ) ] = \frac{kw}{[H {}^( + ) ]} \\ [OH {}^( - ) ] = \frac{1 * {10}^( - 14) }{4.23 * {10}^( - 3) } \\ [OH {}^( - ) ] = 2.36 * {10}^( - 12) M

c.


pH = - log[H {}^( + ) ] \\ pH = - log(4.23 * {10}^( - 3) ) \\ pH = 2.37

d.


pOH = - log[OH {}^( - ) ] \\ = - log(2.36 * {10}^( - 12) ) \\ = 11.63

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