Question

To solve a system of inequalities ayana isolated y in the first equation and then substituted for y in the second equation. what was the result

2y=4x
x^(2)+y=3

Answer 1

x^2+2x=3

Explanation:

Answer 2

(- 3, - 6 ) , (1, 2 )

Explanation:

2y = 4x ( divide both sides by 2 )

y = 2x → (1)

x² + y = 3 → (2)

Substitute y = 2x into (2)

x² + 2x = 3 ( subtract 3 from both sides )

x² + 2x - 3 = 0 ← in standard form

(x + 3)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 1 = 0 ⇒ x = 1

Substitute theses values into (2) for corresponding values of y

x = - 3 : y = 2(- 3) = - 6 ⇒ (- 3, - 6 )

x = 1 : y = 2(1) = 2 ⇒ (1, 2 )