Question

Please explain how - calc ab - see attached photo

Answer 1

D

Explanation:

Set up to different integrals that match the endpoints

so in our case it would look like

`\int\limits^0_(-2) {x} \, dx +\int\limits^1_0 {x+1} \, dx`

now it's just a matter of computing it

`\int\limits^0_(-2) {x} \, dx =x^2\\0^2-(-2)^2=4\\\int\limits^1_0 {x+1} \, dx =(x^2)/(2)+x\\(1)/(2)+1-0=(3)/(2)\\(3)/(2)+4=(11)/(2)`