Question

If r = 1 and 0 = 7pi /6 what is the approximate arc length

0 = theta


A.)1.75

B.)5.498

C.)21.991

D.)7.330

Answer 1

`l = 3.66`

Explanation:

Given

`r =1`

`\theta = (7\pi)/(6)`

Required

The arc length (l)

This is calculated as:

`l= r\theta`

So, we have:

`l = 1 * (7\pi)/(6)`

`l = (7\pi)/(6)`

So, we have:

`l = (7*3.14)/(6)`

`l = 3.66`

None of the options is correct