Question

HELP PLZ ANSWER ASAP!! 30 points!!

A student is asked to prepare 400.0 mL of a 0.25M HCl solution. The students find a bottle labeled “2.0M HCl.” How many mL of the 2.0M solution are needed to prepare the 0.25M solution?
The options are:

25mL
3.0 x10^1 mL
5.0 x 10^1 mL
2.00 x10^1 mL

Answer 1

Step-by-step explanation:

5

Answer 2

5.0 x 10 ^1 mL
Step-by-step explanation:
M1V1 = M2V2
(0.25 M) (400 mL) = (2.0 M) V2
Divide both sides by 2.0 M
V2 = (0.25 M*400mL)/2.0 M
Molarity’s cancel out
V2 = 5.0 x 10^1 mL