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What volume of 9 M sodium hydroxide is required to make 500 mL of 0.1 M sodium hydroxide?

User Yoohoo
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1 Answer

4 votes

Answer:

6mL

Step-by-step explanation:

V₁M₁ = V₂M₂

V₁ = V₂M₂/M₁

V₁ = (500)(0.1)/(9)

V₁ = 5.56mL ≈ 6mL

User LMulvey
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