Question

if you wanted to create 500g of calcium carbonate how much calcium chloride and sodium carbonate would you need?​

Answer 1

555 g of CaCl2

530 g of Na2CO3

Step-by-step explanation:

The equation of this reaction is;

CaCl2 + Na2CO3 ------>CaCO3 + 2NaCl

Number of moles of CaCO3 produced = 500g/100g/mol = 5 moles

If the reaction is in a mole ratio of 1:1 then i need 5 moles of CaCl2 and 5 Moles of Na2CO3.

Mass of CaCl2 required = 5 moles * 111 g/mol = 555 g

Mass of Na2CO3 required = 5 moles * 106 g/mol = 530 g