Question

2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals

Answer 1

241

Explanation:

Given the equation to evaluate :

2^8 −10−15÷3

2^8 = 256

256 - 10 - 15 ÷ 3

From BODMAS principle, we evaluate the divison before subtraction :

-15 ÷ 3 = - 5

256 - 10 -5

256 - 15

= 241