Question

What is the sum of the first ten terms in a geometric series
with a1=
6 and r = 2?

Answer 1

`S_(10) = 682`

Explanation:

Given

`a_1 = 6; r = 2`

Required

`S_{10`

This is calculated as:

`S_n = (a(r^n - 1))/(r - 1)`

So, we have:

`S_(10) = (6 * (2^(10) - 1))/(10 - 1)`

`S_(10) = (6 * (1024- 1))/(9)`

`S_(10) = (6 * 1023)/(9)`

`S_(10) = 682`