Question

What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?

Answer 1

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Step-by-step explanation:

The Hubble's Constant can be found by the following formula:

`v = H_o D\\\\H_o = (v)/(D)`

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

`H_o = (3\ x\ 10^7\ m/s)/(18.52\ x\ 10^(24)\ m)`

H₀ = 1.6 x 10⁻¹⁸ s⁻¹