Question

What will be the change in "velocity" of a 991 kg car if a force of 31,770 N is applied to it for 0.4 seconds?

Answer 1

Answer:
`12.82\ m/s`

Step-by-step explanation:

Given

Mass of car
`m=991\ kg`

Force applied
`F=31,770\ N`

time period
`t=0.4\ s`

Acceleration associated with car

`\Rightarrow a=(F)/(m)\\\\\Rightarrow a=(31770)/(991)\\\\\Rightarrow a=32.05\ m/s^2`

Acceleration is the change in velocity w.r.t time

`\Rightarrow a=(\Delta v)/(\Delta t)\\\\\Rightarrow 32.05=(\Delta v)/(0.4)\\\\\Rightarrow \Delta v=12.82\ m/s`

thus, the change in velocity is
`12.82\ m/s`