Question

If it requires 75.0mL of 0.500M NaOH to neutralize 165.0 mL of an hcl solution what is the concentration of the hcl solution

Answer 1

The concentration of the HCl solution is 0.227 M.

Step-by-step explanation:

To find the concentration of the HCl solution, we can use the formula M1V1 = M2V2, where M1 is the concentration and V1 is the volume of the NaOH solution, and M2 is the concentration and V2 is the volume of the HCl solution.

Given:

• Volume of NaOH solution (V1) = 75.0 mL
• Concentration of NaOH solution (M1) = 0.500 M
• Volume of HCl solution (V2) = 165.0 mL

Plug in the values into the formula:

(0.500 M)(75.0 mL) = M2(165.0 mL)

M2 = (0.500 M)(75.0 mL) / 165.0 mL

M2 = 0.227 M

Therefore, the concentration of the HCl solution is 0.227 M.

Answer 2

0.027 M HCl

Step-by-step explanation:

The chemical equation of the neutralization is:

1 NaOH + 1 HCl -> 1 H2O + 1 NaCl

Because the ratio of NaOH and HCl is 1:1 you can use the M1V1=M2V2 formula.

(75 mL)(0.5 M NaOH) = (165 mL)(M HCl)

It requires 0.027 M HCl.