Question

Please find the Inverse of the Equation (algebra 2)

Answer 1

Inverse would be:

`y = ((1)/(5)x + 3)^3 - 2`

Hope this helps!

Answer 2

`\implies y =((x-3)^3+3)/(5)`

Explanation:

Given :-

• 
  `\sqrt[3]{5x-3}+2`

And we need to find out the inverse of the function. So for that replace x and y. We have ,

`\implies \sqrt[3]{5x-3}+2`

On interchanging x and y :-

`\\\\\implies x = \sqrt[3]{5y-3}+2`

Solve out for y :-

`\implies x -2 =\sqrt[3]{5y-3}\\\\\implies (x-3)^3=5y-3 \\\\\implies 5y = (x-3)^3+3\\\\\implies y =((x-3)^3+3)/(5)`

Hence the inverse of the function is (x-3)³+3/5.