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A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential velocity of the student?

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Answer:

the tangential velocity of the student is 4.89 m/s.

Step-by-step explanation:

Given;

the radius of the circular path, r = 3.5 m

duration of the motion, t = 4.5 s

let the student's tangential velocity = v

The tangential velocity of the student is calculated as follows;


v = (2\pi r)/(t) \\\\v = (2 \pi * 3.5)/(4.5) \\\\v = 4.89 \ m/s

Therefore, the tangential velocity of the student is 4.89 m/s.

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