Question

How many calcium ions are in 0.9 mol of CaCl2?

× 10 Ca2+ ions Enter your answer in scientific notation.

Answer 1

Answer: There are
`5.42 * 10^(23)`
`Ca^(2+)` ions present in 0.9 mol of
`CaCl_(2)`.

Step-by-step explanation:

According to the mole concept, there are
`6.022 * 10^(23)` atoms present in one mole of a substance.

As here, 0.9 mol of
`CaCl_(2)` are present. Also, there is only one atom of Ca is present in a molecule of
`CaCl_(2)`.

Hence, calcium ions present in 0.9 mol of
`CaCl_(2)` are calculated as follows.

`No. of ions = 1 * 0.9 * 6.022 * 10^(23)\\= 5.42 * 10^(23)`

Thus, we can conclude that there are
`5.42 * 10^(23)`
`Ca^(2+)` ions present in 0.9 mol of
`CaCl_(2)`.