Answer:
5648.4 Joules
Step-by-step explanation:
This problem can be solved by the calorimetry formula:
Q = C . m . ΔT
where ΔT indicates the change of temperature
Final T° - Initial T°
m = mass
C = specific heat of water and Q = Heat
We do not have m, but we have the volume of water. We can obtain mass from density.
Volume of water = 10 cm . 4cm . 2.50 cm = 100 cm³
1 cm³ = 1 mL
Density of water = 1 g/mL
Therefore our 100 mL of water is the volume for 100 g. We replace data:
Q = 4.184 J/g°C . 100 g . (32°C - 18.5°C)
Q = 5648.4 Joules