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Her work is shown below. V = two-thirds + 54. V = two-thirds + StartFraction 162 Over 3 EndFraction. V = StartFraction 164 Over 3 EndFraction meter cubed. What is Amie's error?

1 Answer

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The question is incomplete. The complete question is :

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 54 meters cubed. Amie found the volume of the sphere. A sphere with height h and radius r. A cylinder with height h and radius r. Her work is shown below. V = two-thirds + 54. V = two-thirds + StartFraction 162 Over 3 EndFraction. V = StartFraction 164 Over 3 EndFraction meter cubed. What is Amie's error?

Solution :

Amie should have multiplied 54 by two-thirds.

Given that sphere and the cylinder have the same radius as well as same height. The volume of the cylinder is 54 inch cube.

Volume of the sphere =
$(4)/(3)\pi r^3$ .......... (i)

Volume of cylinder =
$\pi r^2h$ ....................(ii)

Therefore, the ratio of sphere volume to cylinder volume is,


$(4)/(3)\pi r^3 : \pi r^2 h$ ......(iii)

Divide both the sides by
$\pi r^2$ , we get


$(4)/(3) \ r : h$ ..........(iv)

We know that the height of the sphere = diameter of the sphere

The diameter of the sphere is D = 2r

Also the sphere height = cylinder height

So, the height of the cylinder = 2r

Therefore, substituting the height of the cylinder as 2r that is represented as h in equation (iv) is given by :


$(4)/(3) \ r : 2r$ .............(v)

Now dividing both the sides by 2r, we get


$(2)/(3) : 1$ ..................(vi)

Thus for equation (vi), we see, sphere volume =
$(2)/(3)$ of the cylinder volume

∴ sphere volume =
$(2)/(3)* 54$

= 36 meter cube

Thus, Amie should have multiplied 54 by
$2/3$ .

User Claudio P
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