36.3k views
5 votes
the figure shows the dimensions of a room in which receptions are held. The room is being carpeted. The three semi-circular parts of the room are congruent. How much carpet is needed? use 3.14 for pie

the figure shows the dimensions of a room in which receptions are held. The room is-example-1
User Paul Fryer
by
6.1k points

1 Answer

3 votes

Answer:

258.39 m^2

Explanation:

Solve for the rectangle:

18 • 12= 216

Now solve for the 3 semi circles:

A = 3.14(3)^2= 28.26/2 = 14.13 •3 = 42.39

Add up the areas:

216 + 42.39 = 258.39

User Carl Verbiest
by
5.7k points