357,434 views
34 votes
34 votes
an astronaut on the moon throws a ball at a velocity of 4.1 m/s straight up. assuming the gravity on the moon is 1/6 that of earths, how high will the ball reach

User Chrispresso
by
2.7k points

2 Answers

22 votes
22 votes

Final answer:

The ball will reach a height of approximately 10.29 meters on the moon when thrown with a velocity of 4.1 m/s.

Step-by-step explanation:

To determine how high the ball will reach on the moon, we can use the formula:

Final Velocity^2 = Initial Velocity^2 + 2 * Acceleration * Distance

Since the ball is thrown straight up, the final velocity at the highest point will be 0 m/s. The initial velocity is 4.1 m/s. The acceleration can be calculated as 1/6 of the acceleration due to gravity on Earth.

By substituting these values into the formula, we can solve for the distance:

0^2 = 4.1^2 + 2 * (1/6 * 9.8) * Distance

Simplifying the equation, we have:

(1/6 * 9.8) * Distance = 4.1^2

(1/6 * 9.8) * Distance = 16.81

Distance = 16.81 / (1/6 * 9.8)

Distance = 16.81 / 1.633

Distance ≈ 10.29 meters

Therefore, the ball will reach a height of approximately 10.29 meters on the moon.

User Oleksandr Pyrohov
by
3.1k points
23 votes
23 votes

Answer:

(1/2)(1.62) t^2 = 1.4

That will give you the time, t

Step-by-step explanation:

hope this helps(✿◡‿◡)

User Jon Lee
by
3.6k points