Answer:
Acids react with carbonates to liberate CO2.
You didn't mention the acid in question.,.
So I'll just pick for myself(HCl) and react with Sodium carbonate
The Equation of reaction would be
2HCl + Na2CO3 ==== 2NaCl + H2O + CO2
It is balanced
Step-by-step explanation:
Given .... 70g of Sodium carbonate.
Reacting Moles of Na2CO3 = mass/molar mass
Molar Mass of Na2CO3 = 23x2 + 12 + 16x3 =106gmol-¹
Mole = 70/106
= 0.66 moles of Sodium Carbonate (Na2CO3)
Looking at our balanced equation...
1 Mole of Na2CO3 reacts to produce 1mole of CO2
Since Their Mole ratio is equal(1:1)...
It now means that an equal amount of CO2 will be produced
Therefore ..... 0.66moles of Na2CO3 Will produce 0.66moles of CO2
So we now have moles of CO2
Recall ... 1mole of any gas at STP contains 22.4L
Therefore ...
0.66moles will contain
= 0.66 x 22.4L
=14.784L of CO2 will be in the products