Question

Balance the below equation:

____NH_3+ 〖____O〗_2 → ____NO+ ____H_2 O
How many grams of NO can be produced from 12 g of NH3 and 12 g of O2?

What is the limiting reactant? What is the excess reactant?

How much excess reactant remains when the reaction is over?

Answer 1

4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

This is an oxidation-reduction (redox) reaction:

4 N-III - 20 e- → 4 NII

(oxidation)

10 O0 + 20 e- → 10 O-II

(reduction)

NH3 is a reducing agent, O2 is an oxidizing agent.

Step-by-step explanation:

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