Factorise fully 3y^(3) -12y

asked Aug 8, 2022 190k views

2 votes

Factorise fully
3y^(3) -12y

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3 votes

Answer:

${3y}^(3) - 12y \\ = 3y( {y}^(2) - 4) \\ = 3y( {y}^(2) - {2}^(2) ) \\ = 3y(y - 2)(y + 2) \\ = 3y(y + 2)(y - 2)$

Aldona answered Aug 10, 2022

7.6k points

3 votes

a^2-b^2=(a+b)(a-b)

a=y b=2

3y(y+2)(y-2)

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