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Graph: Y-3 = 1/2 (x + 2)

Graph: Y-3 = 1/2 (x + 2)-example-1
User Bee San
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8.0k points

2 Answers

3 votes

Move all terms not containing y to the right side of the

equation.

y= X/2+4

Rewrite in slope-intercept form.

y=1/2x+4

Use the slope-intercept form to find the slope and y

intercept.

Slope: 1/2

y-intercept: (0,4)

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values. Answer: (0,4) (2,5)

User David Lane
by
7.8k points
5 votes

The graph should look like a line with a slope of
\((1)/(2)\) passing through the point (0, 4).

To graph the equation
\(y - 3 = (1)/(2)(x + 2)\), we can start by rewriting it in slope-intercept form
(\(y = mx + b\)), where
\(m\) is the slope and
\(b\) is the y-intercept.


\[y - 3 = (1)/(2)(x + 2)\]

Distribute the
\((1)/(2)\) on the right side:


\[y - 3 = (1)/(2)x + 1\]

Now, add 3 to both sides to isolate \(y\):


\[y = (1)/(2)x + 4\]

Now, you can see that the slope
(\(m\)) is
\((1)/(2)\), and the y-intercept
(\(b\)) is 4.

To graph this equation, plot the y-intercept at (0, 4) and use the slope to find additional points. For example, if you move one unit to the right (increase x by 2), you would move up
\((1)/(2)\) units. Connect these points to draw the line.

Therefore the graph should look like a line with a slope of
\((1)/(2)\)passing through the point (0, 4).

Graph: Y-3 = 1/2 (x + 2)-example-1
User Josh French
by
9.3k points

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