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In Figure 5.51 given to the right, m( <ABC) =

32°, m(<BHE) = 42° and m( <ADE) = 48°
Find m(<NAD).​

In Figure 5.51 given to the right, m( <ABC) = 32°, m(<BHE) = 42° and m( &lt-example-1

1 Answer

1 vote

Answer:

122

Explanation:

<HEB=180-(42+32)

=180-74

=106

<DEA=180-106 (straight line)

=74

<NAD=48+74(exterior angle = sum of 2 interior opposite angles)

<NAD=122

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