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What is the equation of the line that passes through (4, 3) and (-4,-1)?

What is the equation of the line that passes through (4, 3) and (-4,-1)?-example-1

1 Answer

3 votes

Answer:


\implies y = (1)/(2)x + 1

Explanation:

Given :-

  • Two points (4,3) and (-4,-1)

And we need to find out the equation of the line passing through the given two points .So here we can use the two point form of the line as ,


\implies (y - y_1) = (y_2-y_1)/(x_2-x_1)(x-x_1)

Let us take that ,


  • (x_1,y_1)=(4,3)

  • (x_2,y_2)=(-4,-1)

Now substitute the respective values ,


\implies (y -3) =(3+1)/(4+4)(x-4) \\\\\implies y - 3 =(4)/(8)(x-4) \\\\\implies y -3=(1)/(2)(x-4) \\\\\implies y -3=(1)/(2)x - 2 \\\\\implies y = (1)/(2)x +3-2\\\\\implies y = (1)/(2)x + 1

Hence the correct option is (2) .

User Micheal Vu
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