Question

What is the molarity of a solution composed

of 4.27 g of potassium iodide (KI) dissolved in
enough water to make 0.304 L of solution?
Answer in units of M.

Answer 1

0.0845 M

Step-by-step explanation:

First we convert 4.27 grams of potassium iodide into moles, using its molar mass:

• Molar Mass of KI = 166 g/mol

• 4.27 g ÷ 166 g/mol = 0.0257 mol

Now we calculate the molarity of the solution, using the number of moles and the given volume:

• Molarity = moles / liters

• Molarity = 0.0257 mol / 0.304 L = 0.0845 M