Answer:
61.6 g
Step-by-step explanation:
Step 1: Write the balanced equation
C + O₂ → CO₂
Since there are 14.6 g of oxygen that remain unreacted by the end of the reaction, oxygen is the reactant in excess and carbon is the limiting reactant, thus the one used to calculate the mass of carbon dioxide produced.
Step 2: Calculate the moles corresponding to 16.8 g of C
The molar mass of C is 12.01 g/mol
16.8 g × 1 mol/12.01 g = 1.40 mol
Step 3: Calculate the number of moles of CO₂ produced from 1.40 moles of C
The molar ratio of C to CO₂ is 1:1. The moles of CO₂ produced are 1/1 × 1.40 mol = 1.40 mol.
Step 4: Calculate the mass corresponding to 1.40 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
1.40 mol × 44.01 g/mol = 61.6 g