Question

Please hurry need done asap

Answer 1

Last option is the correct answer

`(\sqrt[3]{2x - 6})^(3) = (- \sqrt[3]{2x + 6})^(3)`

Explanation:

`\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0 \\ \sqrt[3]{2x - 6} = - \sqrt[3]{2x + 6}\\ cubing \: both \: sides\\ (\sqrt[3]{2x - 6})^(3) = (- \sqrt[3]{2x + 6})^(3)`

Answer 2

the answer is the third equation

hope it helps