170k views
5 votes
six subtracted from a number is equal to one fourth of the sum of the number and 45 find the number ​

2 Answers

3 votes

Number = 23

Explanation:

Given:

Six is subtracted from a number.

The result is equal to one fourth of the sum of the number and 45 find the number .

To Find:

What is the number ?

Solution: Let the number be x.

➟ Subtracting 6 from x.

➟ (x – 6) ㅤㅤㅤㅤㅤ(eqⁿ 1)

Now,

➙ One fourth of sum of the number + 45

➙ 1/4 × x + 45

➙ x + 45/4ㅤㅤㅤㅤ(eqⁿ 2)

According to the question,

Equation 1 = 2

⟹ (x – 6) = x + 45/4

⟹ 4(x – 6) = x + 45

⟹ 4x – 24 = x + 45

⟹ 4x – x = 45 + 24

⟹ 3x = 69

⟹ x = 69/3

⟹ x =23

Hence, the number is 23.

User Shannen
by
3.9k points
5 votes


\boxed{\large{\bold{\blue{ANSWER~:) }}}}

Given :

Six is subtracted from a number and the resulting number is equal to one fourth of the sum of the number and 45 .

Exigency To Find :

The Number .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's say that the number is a

AccordingtotheQuestion

:

⠀⠀⠀━━━ Six is subtracted from a number is equal to one fourth of the sum of the number and 45 .


\begin{gathered}\qquad \dashrightarrow \sf Number \: - \: 6 \: =\: (1)/(4) th * \bigg( Sum_((Number \:and \:45))\bigg) \\\\\qquad \dashrightarrow \sf Number \: - \: 6 \: =\: (1)/(4) th * \bigg( Number \:+ \:45\bigg) \\\\\qquad \dashrightarrow \sf a \: - \: 6 \: =\: (1)/(4) * \bigg( a + 45\bigg) \\\\\qquad \dashrightarrow \sf a \: - \: 6 \: =\: (1)/(4)\bigg( a + 45 \bigg) \\\\\qquad \dashrightarrow \sf a \: - \: 6 \: =\: (a)/(4) + (45)/(4) \\\\\qquad \dashrightarrow \sf a \: - \: 6 \: =\: (a + 45)/(4) \\\\\qquad \dashrightarrow \sf 4\bigg( a \: - \: 6 \bigg)\: =\: a + 45 \\\\\qquad \dashrightarrow \sf 4a \: - \: 24\: =\: a + 45 \\\\\qquad \dashrightarrow \sf 4a \: \: =\: a + 45 + 24\\\\\qquad \dashrightarrow \sf 4a \: \: =\: a + 69\\\\\qquad \dashrightarrow \sf 4a \:- a \: =\: 69\\\\\qquad \dashrightarrow \sf 3a \: =\: 69\\\\\qquad \dashrightarrow \sf a \: =\: \cancel {(69)/(3)}\\\\\qquad \dashrightarrow \sf a \: =\: 23\\\\\qquad \therefore\:\: \pmb{\underline{\purple{\bold{ \:a = 23} }} }\:\:\bigstar \\\end{gathered}

  • Here a denotes the number which is 23 .

∴Hence,Thenumberis23.

User Chatura Dilan
by
4.4k points