Question

If the pressure in a gas cylinder is heated to 354.2 K with the pressure of 2.64 atm that was the initial temperature if the initial pressure was 1.25 atm

Answer 1

Initial temperature of the gas cylinder was 167.7K

Step-by-step explanation:

Based on Gay-Lussac's law, the pressure of a gas under constant volume is directly proportional to its absolute temperature. The equation is:

P1*T2 = P2*T1

Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.

Replacing:

P1 = 1.25atm

T2 = 354.2K

P2 = 2.64atm

T1 = ?

1.25atm*354.2K = 2.64atm*T1

167.7K = T1

Initial temperature of the gas cylinder was 167.7K