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In the system of equations 4x + 2y = 10 and 12x - 3y = 3, what is the solution?

Hint: SOLVE BY ELIMINATION

User Tocco
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1 Answer

5 votes

Answer:

solution = (3, 11)

Explanation:

4x + 2y = 10

*subtract 4x from both sides*

2y = -4x + 10

*divide by 2* --> y = -2x +5

12x - 3 y = 3

*add 3y to both sides*

12x = 3y + 3

*subtract 3 form both sides*

12x - 3 = 3y

*divide by 3* --> y = 4x - 3)

2x + 5 = 4x - 1

*subtract 2x form both sides*

5 = 2x -1

*add 1 to both sides*

6 = 2x

*divide by 2x* --> x = 3

y = 2(3) + 5 (plug in 3 for x to solve for y)

y = 6 + 5

y = 11

User MikeRand
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