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Una onda cuya frecuencia es igual a 550 Hz, se propaga en el aire. ¿ cual es su longitud de onda y su periodo?

1 Answer

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Answer:

The wavelength of the wave is
5.45* 10^5\ m and time period is 0.0018 s.

Step-by-step explanation:

The given question is, "A wave whose frequency is equal to 550 Hz, propagates in the air. What is its wavelength and its period?"

Given that,

The frequency of a wave, f = 550 Hz

The time period of a wave,


T=(1)/(f)\\\\T=(1)/(550)\\\\T=0.0018\ s

Wavelength,


\lambda=(c)/(f)\\\\\lambda=(3* 10^8)/(550)\\\\\lambda=5.45* 10^5\ m

So, wavelength of the wave is
5.45* 10^5\ m and time period is 0.0018 s.

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