Answer:
0.135%
Explanation:
Given :
Mean, m = 60
Standard deviation, σ = 5
x = 45
The Zscore = (x - m) / σ
Z = (45 - 60) / 5 = - 15 / 5 = - 3
P(Z < - 3) = 0.0013499
0.0013499 * 100%
= 0.13499%
Only about 0.135% scored below 45
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