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Gas is collected over water at 25 °C. The pressure in the container was 0.13 atm. Using a vapor pressure chart, what is the pressure of the dry gas?

User Mmuzahid
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Answer:


p_(gas)=0.0987atm

Step-by-step explanation:

Hello there!

In this case, according to this problem about partial pressures, we first use the Dalton's law in order to realize how the vapor pressure of water and the partial pressure of the gas contribute to the total pressure:


P_T=p_(H_2O)+p_(gas)

Thus, since the vapor pressure of water at 25 °C is 0.0313 atm, the partial pressure of the gas turns out to be:


p_(gas)=P_T-p_(H_2O)\\\\p_(gas)=0.13atm-0.0313atm\\\\p_(gas)=0.0987atm

Regards!