Question

Which is the equation of the line through the point (−3, 8) that is perpendicular to the line y=14x+12? CLEAR SUBMIT y=−14x−5 y=−4x−4 y=−4x+35 y=4x+29

Answer 1

Answer:
`x+14y=109`

Explanation:

Given

The line passes through
`(-3,8)` and is perpendicular to the given line
`y=14x+12`

Comparing
`y=14x+12` with line
`y=mx+c` to get the slope i.e.
`\text{Slope=}14`

Suppose m is the slope of the required line

And the product of the slope of perpendicular lines is
`-1`

`\therefore 14(m)=-1\\\\\Rightarrow m=-(1)/(14)`

The equation of the required line is

`\Rightarrow (y-8)/(x+3)=-(1)/(14)\\\\\Rightarrow -14y+14* 8=x+3\\\Rightarrow x+14y=112-3\\\Rightarrow x+14y=109`

None of the given options is correct.