Answer:
c. 9, 1, 0, 1, 9; Graph A
Explanation:
The given equation is presented as follows;
y = x²
The values of 'x' are -3, -1, 0, 1, 3
The range of the values of 'y' are; (-3)² = 9, (-1)² = 1, 0² = 0, 1² = 1, 3² = 9
9, 1, 0, 1, 9
The completed table is presented as follows;

The values can be extended using the equation to include points, x = -2, y = (-2)² = 4, and x = 2, y = 2² = 4
To give a graph that passes through the point (-2, 4) and (2, 4)
Given that the coefficient of x² is positive, the graph opens up
Therefore, the graph that best represent the equation is c, 9, 1, 0, 1, 9; Graph A On the coordinate plane, a parabola opens up and goes through (-2, 4), has a vertex at (0, 0), and goes through (2, 4).